Tugas Anda 2.2 Tikungan Miring Licin

Gaya 33 -3-59-:-7-4-=-91:345?:3.-?-718-6-:-0-?57:3-:6-8-: D-:395=5:30-:7--=1=4-?57-: . 1=0--?0-7;9;:1: 3-D- 0-8-9 -=-4 =-05-8 71 -? ?57:3-: 6-8-: D-5? 7;9;:1: 3-D- :;=9-8 5: 0-:7;9;:1:3-D-3117-:?-?5 ; 18?-:710- 3-D-?1=1.?.1=2:351.-3-53-D-1:?=51?-8 18-6-:9-75999;.58 -3-= ?50-7 185 0--? 051=;814 1.-3-5 .1=57? 9-7 r 5: ; 9-7 r 5: ; 9-7 r 5: ; 9-7 r G ;.58 ?50-7 .1=31=-7 -0- 9.-+ 145:33- + -9.58-=-471-?-;5?52 ; G , 5: ; G 5: ; G 5: G 57- .+ 5 05.-35 01:3-: .+ 5 051=;814 5: ; ; 5: ; ; 9-7 g 9-7 ?-: ?-: g G -=5 1=-9--: ?1=1.? 0--? 055987-: .-4B- 0? 7195=5:3-: 6-8-: 0-:717--=-:6-8-: .1=1:3-=4?1=4-0-8-69-7599 9;.58 :?7 919.18;7 -3-= ?50-7 ?1=6-05 185 Kata Kunci • gaya gesek kinetik • gaya gesek statis • koefisien gaya gesek ;.589181B-?5?57:3-:6-8-:D-:36-=56-=57181:37:3-::D-9 57-0? 7195=5:3-:6-8-: F?1:?7-:711-?-:9-75999;.58D-:3051=.;8147-: :?77;:055 - 6-8-:855:7-=1:-.1=-5=3117-:05-.-57-: . 6-8-:71=5:301:3-:7;12551:3117-:?-?5 -9.58 9 3 - +:?77;:0556-8-:855:3:-7-:1=-9--: 9-7 ?-: 9 9 ?-: 9-7 9 Contoh 2.6 Gambar 2.10 Diagram gaya pada mobil yang sedang melaju pada lintasan melingkar yang miring dan kasar. N cos N N sin f s cos f s sin f s 34 Mudah dan Aktif Belajar Fisika untuk Kelas XI 4 kg 3 kg 3 kg A B C 1:0-.1=9--73?1=81?-705-?-.50-:30-?-= 1-=7;12551:3117-:?-?5-:?-=-.1:0-0-:-8- -0-8-4 57- 9 .1=--.1-=3-D-D-:3 05.?47-::?791:-=57.1:0-71?57-?1-?-7-: .1=31=-7 -8;7.1=9--73?1=81?-705-?-8-:?-57--= -0- .-8;70571=6-7-:3-D-91:0-?-=-3-=.-8;7?1-? -7-:.1=31=-7 1?18-4.-8;7.1=31=-7051=87-:3-D- 45:33-.-8;7.1=31=-701:3-:711-?-:?1?- 5?:37;12551:3117-:?-?5-0-.-8;70-:8-:?-5 1:0-.1=9--73?1=81?-7-0-1.-4.50-:30-?-= -0-.1:0-.171=6-3-D-4;=5E;:?-81.1-= 57- 7;12551:3117-:75:1?57-:?-=-.1:0-0-:.50-:3 .1=--7-41=1-?-:D-:305-8-95.1:0- -8;7.1=9-- 73?1=81?-705-?-8-:?-50-:05?-=57 ;8143-D-95=5:371-?-0-:919.1:?70? F 01:3-: -=-4 4;=5E;:?-8 57- 7;12551: 3117-: 75:1?57 0-: ?-?5 9-5:39-5:3 0-: 1=?- 1=1-?-:3=-A5?-59 ?1:?7-:3-D-3117-: D-:3.171=6--:?-=-.-8;70-:8-:?-5 1:0-.1=9--73?1=81?-7-0-.50-:37--= -=571-0--:05-9.1:0-05.1=53-D- ?1?-18-9- 17;: 1?18-491:1946-=-7 9 71-0--: .50-:3 98-5 855: 19=:- 1=--7-41=5:0-4-:.1:0- 1=4-?57-:3-9.-=.1=57? --?0581-7-:710-.1:0-919585751=1-?-: 9 57-5: .1=--7;12551:3117-:?-=- .1:0-0-:.50-:3 53-.-4.1:0-05:11=?5-0-3-9.-= ;12551: 3117 75:1?57 .1:0- 0-: ?1=4-0- .50-:30-?-=.1=?=??=? 0-: 57-.1:0- 0581-7-: .1=--7-4 1=1-?-: 71?53- .1:0- ?1=1.? 1.-4?57:3-:6-8-:=-D-D-:30--?05-:33-1.-3-5 .-35-:85:37-=-:.1=6-=56-=59-7-:05.-:3:;814 1;=-:3-485.-:3:-: +:?7711=8-:?1=1.?-485 .-:3:-: 91:-:D-7-: 71-0- 1;=-:3 -485 2557- .1=--7-47195=5:3-:?57:3-:145:33-9;.580--? 918-6 01:3-: 711-?-: 9 ?-:- 718-= 0-=5 85:?--: 9 Tes Kompetensi Subbab A .+ 110+ F 37° m B = 8 k g m A = 2 kg . +:?77;:0556-8-:-:7--=3:-7-:1=-9--: 9-7 ?-: ?-: g ?-: ?-: 9-7 9 9 9 Tantangan untuk Anda Sebuah benda bermassa m meluncur pada bidang miring kasar. Sudut kemiringan bidang tersebut adalah . Jika benda berhenti setelah berpindah sejauh x akibat gaya gerak, buktikan bahwa: 1 cos m x w g -8-9-7?5A5?-2557-D-:3?18-4:0-8-77-:05..-.5:5:0-0--?91:1:?7-: 1-=-8-:3:33-D-3117?-?5-?.1:0- 1905-:01:3-:918-77-:. ?5?5:58-5?1=1.?710-8-91=-9--: :0-0--?7-::58-5 s ?1=1.? 17-=-:3=-:-:38-4-?1=;.--:101=4-:-:?791:0--?7-::58-5 857-:8-4 =-:-:3-:1=;.--:?1=1.?0-:7987-:71-0-3=:0- Mari Mencari Tahu