= 0,6600 0 + 0,1999 Rp. 7.600.000,- + 0,0399 Rp. 7.600.000,- + 0,0999 Rp. 93.425.000
= Rp. 1.519.240,- + Rp. 303.240,- + Rp. 9.333.157,5,- = Rp 11.155.637,5,-
5. P
4
= 0,5575 0 + 0,1892 0 + 0,0878 Rp. 93.425.000,- + 0,1655 Rp. 93.425.000 Pemeliharaan corective pada status 3 dan 4
= Rp. 8.202.715,- + Rp. 15.461.837,5 = Rp 23.664.552,5,-
2. Biaya Rata-rata Ekspektasi Holzma Item 2
Sehingga didapatkan perbandingan biaya rata-rata ekspektasi pemeliharaan yang dilakukan oleh perusahaan dengan pemeliharaan usulan adalah sebagai berikut;
1. P = Rp. 11.837.237,5 ,-
= 0,4166 0 + 0,1167 0 + 0,2500 0 + 0,2167 Rp. 54.625.000
2. P
1
= 0,3448 0 + 0,3379 0 + 0,1379 Rp. 2.875.000,- + 0,1793 Rp. 54.625.000 Pemeliharaan corective pada status 4 dan pemeliharaan pencegahan pada status
3
= Rp. 396.462,5,- + Rp. 9.794.262,5,-
= Rp. 10.190.725,- 3. P
2
= 0,6579 0 + 0,1053 Rp. 2.875.000,- + 0,0789 Rp. 54.625.000,- + 0,1579 Rp. 54.625.000,-
Pemeliharaan corective pada status 3 dan 4, dan pemeliharaan pencegahan pada status 2
= Rp.302.737,5,- + Rp. 4.309.912,5,- + Rp. 8.625.287,5,- = Rp. 13.237.937,5,-
4. P
3
= 0,6098 0 + 0,1707 Rp. 2.875.000,- + 0,0731 Rp. 2.875.000,- + 0,1463 Rp. 54.625.000,-
Pemeliharaan corective pada status 4 dan pemeliharaan pencegahan pada status 2 dan 3
= Rp. 490.762,5,- + Rp. 210.162,5,- + Rp. 7.991.637,5,- = Rp. 8.692.562,5,-
5. P
4
= 0,5555 0 + 0,1556 0 + 0,1111 Rp. 54.625.000,- + 0,1778 Rp. 54.625.000,- Pemeliharaan corective pada status 3 dan 4
= Rp 6.068,837,5,- + Rp. 9.712.325,- = Rp. 15.781.162,5,-
3. Biaya Rata-rata Ekspektasi Rover Item 3
Sehingga didapatkan perbandingan biaya rata-rata ekspektasi pemeliharaan yang dilakukan oleh perusahaan dengan pemeliharaan usulan adalah sebagai berikut:
1. P = Rp.6.870.370,-
= 0,5390 0 + 0,1172 0 + 0,2149 0 + 0,1289 Rp. 53.300.000,-
2. P
1
= 0,3458 0 + 0,4060 0 + 0,1654 Rp. 3.712.500,- + 0,0827 Rp. 53.300.000 Pemeliharaan corective pada status 4 dan pemeliharaan pencegahan pada status
3 .
= Rp. 614.047,5,- + Rp. 4.407.910 = Rp. 5.021.957,5,-
3. P
2
= 0,8069 0 + 0,0877 Rp. 3.712.500,- + 0,0702 Rp. 53.300.000,- + 0,0351 Rp. 53.300.000,-
Pemeliharaan corective pada status 3 dan 4, dan pemeliharaan pencegahan pada status 2
= Rp.325.586,25,- + Rp. 3.741660,- + Rp 1.870.830,- = Rp. 5.938.076,25,-
4. P
3
Pemeliharaan corective pada status 4 dan pemeliharaan pencegahan pada status 2 dan 3
= 0,7540 0 + 0,1476 Rp. 3.712.500,- + 0,0656 Rp. 3.712.500,- + 0,0328 Rp. 53.300.000,-
= Rp. 547.965,- + Rp. 243.540,- + Rp. 1.748.240,- = Rp. 2.539.745,-
5. P
4
= 0,6865 0 + 0,1493 0 + 0,1095 Rp. 53.300.000,- + 0,0547 Rp.53.300.000,-
Pemeliharaan corective pada status 3 dan 4
= Rp 5.836.350,- + Rp. 2.915.510,- = Rp. 8.751.860,-
1. Selco
1.1
Po Pemeliharaan korektif pada status 4
Modules-1 Modules-2 Input Data Solution Options Help - MKV Problem Specification
∙ Enter the following fields to define your problem. ∙ Specify if you want to define the state names.
∙ Specify if you know the intial state probabilities. ∙ Specify if you know the costprofit associated with each state.
Problem Name? [Selco ] Number of states? [4 ]
State name: Default Sn ♦ You define
Initial state probabilities: Known ♦ Unknown
Costprofit of states: Known ♦ Unknown
OK Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help – MKV Transition Probabilities for Selco
│From \ To:│ S1 S2 S3 S4 S1
│[0.5455 ][0.2424 ][0.0606 ][0.1515 ] S2
│[0 ][0.2857 ][0.2857 ][0.4286 ] S3
│[0 ][0 ][0.5 ][0.5 ] S4
│[1 ][0 ][0 ][0 ]
OK PgUp PgLt PgRt Help Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help - MKV Steady State Solution for
07-01-2004 05:18:30 Page: 1 of 1 State
│ State │ Recurrence │ State │ State │ Recurrence Name
│Probability │ Time │ Name │Probability │ Time S1
│ .4741674 │ 2.10896 │ S3 │ .1494132 │ 6.69284 S2
│ .1609102 │ 6.214644 │ S4 │ .2155091 │ 4.64017 Expected CostProfit = 0 Elapsed CPU Seconds = 0
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1.2 P1 Pemeliharaan korektif pada status 4 dan pemeliharaan Pencegahan pada
Status 3 .
Modules-1 Modules-2 Input Data Solution Options Help - MKV Problem Specification
∙ Enter the following fields to define your problem. ∙ Specify if you want to define the state names.
∙ Specify if you know the intial state probabilities. ∙ Specify if you know the costprofit associated with each state.
Problem Name? [Selco ] Number of states? [4 ]
State name: Default Sn ♦ You define
Initial state probabilities: Known ♦ Unknown
Costprofit of states: Known ♦ Unknown
OK Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help - MKV Transition Probabilities for Selco
From \ To: │ S1 S2 S3 S4
S1 │[0.5455 ][0.2424 ][0.0606 ][0.1515 ]
S2 │[0 ][0.2857 ][0.2857 ][0.4286 ]
S3 │[0 ][1 ][0 ][0 ]
S4 │[1 ][0 ][0 ][0 ]
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Modules-1 Modules-2 Input Data Solution Options Help - MKV Steady State Solution for Selco
07-01-2004 05:35:11 Page: 1 of 1 State
│ State │ Recurrence │ State │ State │ Recurrence Name
│Probability │ Time │ Name │Probability │ Time S1
│ .4125363 │ 2.424029 │ S3 │ .1083223 │ 9.231709 S2
│ .2916437 │ 3.428842 │ S4 │ .1874977 │ 5.333398 Expected CostProfit = 0 Elapsed CPU Seconds = 0
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1.3 P2 Pemeliharaan Korektif Pada Status 3 dan 4 dan Pemeliharaan Pencegahan
pada Status 2 .
Modules-1 Modules-2 Input Data Solution Options Help - MKV Problem Specification
∙ Enter the following fields to define your problem. ∙ Specify if you want to define the state names.
∙ Specify if you know the intial state probabilities. ∙ Specify if you know the costprofit associated with each state.
Problem Name? [Selco ] Number of states? [4 ]
State name: Default Sn ♦ You define
Initial state probabilities: Known ♦ Unknown
Costprofit of states: Known ♦ Unknown
OK Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help - MKV
Transition Probabilities for Selco From \ To:
│ S1 S2 S3 S4 S1
│[0.5455 ][0.2424 ][0.0606 ][0.1515 ] S2
│[1 ][0 ][0 ][0 ] S3
│[1 ][0 ][0 ][0 ] S4
│[1 ][0 ][0 ][0 ] OK PgUp PgLt PgRt Help Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help - MKV Steady State Solution for Selco
07-01-2004 05:43:55 Page: 1 of 1 State
│ State │ Recurrence │ State │ State │ Recurrence Name
│Probability │ Time │ Name │Probability │ Time S1
│ .6875215 │ 1.4545 │ S3 │ .0416638 │ 24.00165 S2
│ .1666552 │ 6.000413 │ S4 │ .1041595 │ 9.60066 Expected CostProfit = 0 Elapsed CPU Seconds = 0
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1.4 P3 Pemeliharaan korektif pada status 4 dan Pemeliharaan Pencegahan pada
status 2 dan 3 .
Modules-1 Modules-2 Input Data Solution Options Help - MKV Problem Specification
∙ Enter the following fields to define your problem. ∙ Specify if you want to define the state names.
∙ Specify if you know the intial state probabilities. ∙ Specify if you know the costprofit associated with each state.
Problem Name? [Selco ] Number of states? [4 ]
State name: Default Sn ♦ You define
Initial state probabilities: Known ♦ Unknown
Costprofit of states: Known ♦ Unknown
OK Print Cancel
Modules-1 Modules-2 Input Data Solution Options Help - MKV Transition Probabilities for Selco
From \ To: │ S1 S2 S3 S4
S1 │[0.5455 ][0.2424 ][0.0606 ][0.1515 ]
S2 │[1 ][0 ][0 ][0 ]
S3 │[0 ][1 ][0 ][0 ]
S4 │[1 ][0 ][0 ][0 ]
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Modules-1 Modules-2 Input Data Solution Options Help - MKV Steady State Solution for Selco
07-01-2004 05:55:37 Page: 1 of 1 State
│ State │ Recurrence │ State │ State │ Recurrence Name
│Probability │ Time │ Name │Probability │ Time S1
│ .6600224 │ 1.5151 │ S3 │ 0.039997 │ 25.00165 S2
│ .1999868 │ 5.00033 │ S4 │ .0999934 │ 10.00066 Expected CostProfit = 0 Elapsed CPU Seconds = 0
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