Existence: Proof of Theorem 2.2.6 Strong uniqueness: Proof of Theorem 2.2.9
Lemma 2.5.2 Let D be regular and 0
∈ D. Then there exist a function r ∈
C
2
D and a constant K
∈ 0, ∞ with the following properties: 0 r x
≤ 1 x
∈ D r x
= 0 x
∈ ∂ D −x · ∇rx = K
x ∈ ∂ D.
2.5.20
Proof of Lemma 2.5.2: Recall the definition of a regular set in section 2.2.4 and the function m associated with it. The function x
→ x · nx = x · ∇mx is
C
2
and strictly positive on ∂ D, so we can find a strictly positive function φ ∈
C
2
D such that in an open neighbourhood of ∂ D:
φ xx
· nx = 1. 2.5.21
Define r x :
= −φxmx x
∈ D. 2.5.22
Then r ∈
C
2
D and, for all x ∈ ∂ D, ∇rx is parallel to nx and satisfies
−x · ∇rx = φxx · ∇mx = 1. We can multiply r with a constant to get r
≤ 1.
Lemma 2.5.3 Let D
′
⊃ D be regular. For x ∈ ∂ D
′
, let nx be the normal to D
′
in x. For x ∈ D, let
lx : = inf{|x − y| : y ∈ ∂ D}.
2.5.23 Assume that, for all x
n
∈ D, x ∈ ∂ D
′
∩ ∂ D with x
n
→ x as n → ∞, lim sup
n →∞
gx
n
lx
n
x · nx.
2.5.24 Then there exists a function h
∈
C
D
′
such that ≤ hx
x ∈ D
′
lim
n →∞
hx
n
= ∞ x
n
→ x ∈ ∂ D
′
A
hx ≤ 1
x ∈ D.
2.5.25
Proof of Lemma 2.5.3: Extend g by putting g ≡ 0 on D
′
\D, so that 2.5.24 holds for all x
n
∈ D
′
with x
n
→ x ∈ ∂ D
′
. Let r be as in Lemma 2.5.2. The idea will be to find a function f
∈
C
2
0, 1] such that hx :
= f rx 2.5.26
satisfies 2.5.25.
For any f ∈
C
2
0, 1] we have ∇ f rx = f
′
r x ∇rx
f r x = f
′′
r x ∇rx · ∇rx + f
′
r x r x
A
f r x =
− x · ∇rx + gx rx f
′
r x +
gx |∇rx|
2
f
′′
r x, 2.5.27
where the first two formulas follow from
∂ ∂
x
i
f r x = f
′
r x
∂ ∂
x
i
r x
i ∂
2
∂ x
i 2
f r x =
i ∂
∂ x
i
f
′
r x
∂ ∂
x
i
r x =
i
f
′′
r x
∂ ∂
x
i
r x
∂ ∂
x
i
r x + f
′
r x
∂
2
∂ x
i 2
r x. 2.5.28
We want estimates on the two terms in the formula for
A
f r x. To that aim, we define functions a, b
∈
C
[0, 1] by az :
= max{gx|∇rx|
2
: r x = z}
bz : = min{−x · ∇rx + gx rx : rx = z},
2.5.29 We have
b0 = K
lim sup
z →0
az z
K . 2.5.30
Indeed, the first equation is trivial. For the second one, note that az
z = max
gx|∇rx|
2
r x : r x
= z ,
2.5.31 where, by 2.5.24, for each x
n
∈ D
′
with x
n
→ x ∈ ∂ D
′
lim sup
n →∞
gx
n
|∇rx
n
|
2
r x
n
= lim sup
n →∞
gx
n
lx
n
lim
n →∞
lx
n
r x
n
|∇rx
n
|
2
x · nx|∇rx| = −x · ∇rx = K .
2.5.32 Here, the last two equalities follow from Lemma 2.5.2. Using compactness, we
arrive at 2.5.30. We have thus found functions a, b
∈
C
[0, 1] such that −x · ∇rx + gx rx ≥ brx
gx |∇rx|
2
≤ arx lim sup
z →0
az z
b0. 2.5.33
We can change a such that a 0 on 0, 1] while 2.5.33 continues to holds. Applying Lemma 2.5.1 to these functions a and b, we find a function f satisfying
2.5.5, 2.5.6 and 2.5.8. Since b0 0, we see that there exists an ε 0 such that
f
′′
z 0 z
∈ 0, ε. 2.5.34
Combining this with 2.5.6, 2.5.27 and 2.5.33, we see that
A
hx ≤ 1
x ∈ D, rx ε,
2.5.35 where hx :
= f rx as in 2.5.26. But x →
A
hx is continuous on the compact set
{x ∈ D : rx ≥ ε}, so multiplying h by a constant we arrive at a function satisfying 2.5.25.
Lemma 2.5.4 Let D be a finite intersection of regular sets. Assume that for all x
∈ ∂ D, all x
n
∈ D with x
n
→ x, and each normal nx to D in x: lim sup
n →∞
gx
n
|x − x
n
| x
· nx. 2.5.36
Then there exists a function h ∈
C
2
D such that ≤ hx
A
hx ≤ 1
2.5.37 and such that hx
n
→ ∞ for all x
n
→ x ∈ ∂ D.
Proof of Lemma 2.5.4: Let D
=
n i
=1
D
i
, where the D
i
are regular. For each D
i
the assumptions in Lemma 2.5.3 are satisfied. In particular, 2.5.36 implies 2.5.24. Let h
i
∈
C
2
D
i
be the function constructed in Lemma 2.5.3. Then h
=
1 n
n i
=1
h
i
satisfies our requirements.
Lemma 2.5.5 Let D and g be as in Lemma 2.5.4, and let X
x t
t ≥0
be a solution to the martingale problem for A with X
x
= x ∈ D. Then P[X
x t
∈ D ∀t ≥ 0] = 1. 2.5.38
Proof of Lemma 2.5.5: Let h be the function mentioned in Lemma 2.5.3. For
H ∞ we introduce a stopping time τ
H
by τ
H
: = inf{t ≥ 0 : hX
x t
= H }. 2.5.39
We can extend h outside {x ∈ D : hx ≤ H } to a function in
C
2
D. From the martingale problem we get
E[hX
t ∧τ
H
] = hx + E[
t ∧τ
H
A
hX
s
ds] ≤ hx + E[t ∧ τ
H
]. 2.5.40
Here E[hX
t ∧τ
H
] ≥ H P[τ
H
≤ t] and E[t ∧ τ
H
] ≤ t, so
P[τ
H
≤ t] ≤ hx
+ t H
. 2.5.41
Therefore P[hX
x s
H ∀0 ≤ s ≤ t] ≥ 1 −
hx + t
H .
2.5.42 Letting H
↑ ∞ so that {x ∈ D : hx H } ↑ D, we find that P[X
x s
∈ D ∀0 ≤ s ≤ t] = 1. 2.5.43
Letting t ↑ ∞ we obtain Lemma 2.5.5.
Proof of Theorem 2.2.9: Define D
n
: = {x ∈ D : gx
1 n
}. Note that if g is Lipschitz on D
n
with constant L
n
, then √g is Lipschitz on D
n
with constant n L
n
. Let X
t t
≥0
and ˜ X
t t
≥0
be solutions of 2.2.7 with X = ˜X
, adapted to the same Brownian motion. Define stopping times
τ
n
: = inf{t ≥ 0 : X
t
∈ ∂ D
n
}, 2.5.44
and define ˜τ
n
similarly for ˜ X
t t
≥0
. Now follow the proof of Theorem 5.2.5 in [22], to see that the processes X and ˜
X are indistinguishable up to time τ
n
∧ τ
n
, where by Lemma 2.5.5, τ
n
∧ ˜τ
n
↑ ∞ as n ↑ ∞.