Perhitungan Pengujian Analisis Regresi Ganda
I. Analisis Ganda Hipotesis IV
Diketahui:
1
X ∑
= 1876
2 1
X ∑
= 58364
2 1
X X
∑
= 56062
2
X ∑
= 1856
2 2
X ∑
= 56656
3 1
X X
∑ = 37415
3
X ∑
= 1222
2 3
X ∑
= 26354
3 2
X X
∑ = 36904
Y ∑ = 470,2
2
Y ∑
= 3588,235
Y X
1
∑
= 14315,3
1
X = 30,25806452
3
X
= 19,70967742
Y X
2
∑
= 14125,55
2
X = 29,93548387 Y
= 7,583870968 Y
X
3
∑ = 9360,55
2
Y ∑
= 3588,235 Ν = 62
Dari data di atas maka dapat dihitung nilai-nilai sebagai berikut:
87097 ,
1599 62
1876 58364
2 2
1 2
1 2
1
= −
= Ν
∑ −
∑ →
∑ X
X x
74194 ,
1092 62
1856 56656
2 2
2 2
2 2
2
= −
= Ν
∑ −
∑ →
∑ X
X x
77419 ,
2268 62
1222 26354
2 2
3 2
3 2
3
= −
= Ν
∑ −
∑ →
∑ X
X x
298871 ,
22 62
2 ,
470 235
, 3588
2 2
2 2
= −
= Ν
∑ −
∑ →
∑ Y
Y y
96774 ,
96 62
1856 1876
56062
2 1
2 1
2 1
− =
− =
Ν ∑
∑ −
∑ →
∑ X
X X
X x
x 64516
, 439
62 1222
1876 37415
3 1
3 1
3 1
= −
= Ν
∑ ∑
− ∑
→ ∑
X X
X X
x x
83871 ,
322 62
1222 1856
36904
3 2
3 2
3 2
= −
= Ν
∑ ∑
− ∑
→ ∑
X X
X X
x x
95806 ,
87 62
2 ,
470 1876
3 ,
14315
1 1
1
= −
= Ν
∑ ∑
− ∑
→ ∑
Y X
Y X
y x
88548 ,
49 62
2 ,
470 1856
55 ,
14125
2 2
2
= −
= Ν
∑ ∑
− ∑
→ ∑
Y X
Y X
y x
Setelah memperoleh nilai-nilai di atas maka dapat dibuat persamaannya:
87,95806 = 1599,87097 a
1
+ -96,96774 a
2
+ 439,64516 a
3
………………..1 49,88548 = - 96,96774 a
1
+ 1095,74194 a
2
+ 322,83871 a
3
…………………2 93,059677 = 439,64516 a
1
+ 322,83871 a
2
+ 2268,77419 a
3
…………………3
Persamaan 1 2
87,95806 = 1599,87097 a
1
+ -96,96774 a
2
+ 439,64516 a
3
……..1 X 96,96774 49,88548 = - 96,96774 a
1
+ 1095,74194 a
2
+ 322,83871 a
3
……..2 X 1599,87097
→
8529,094293 = 155135,8723 a
1
+ -9402,742601 a
2
+ 42631,39757 a
3
79810,33128 = -155135,8723 a
1
+ 1753045,72 a
2
+ 516500,2801 a
3
+ 88339,42557 = 1743642,977 a
2
+ 559131,6777 a
3
………………..4
Persamaan 1 3
87,95806 = 1599,87097 a
1
+ -96,96774 a
2
+ 439,64516 a
3
……1 X 439,64516 93,059677 = 439,64516 a
1
+ 322,83871 a
2
+ 2268,77419 a
3
……2 X 1599,87097
→
38670,33536 = 703375,5286 a
1
+ -42631,39757 a
2
+ 193287,8667 a
3
148883,4757 = 703375,5286 a
1
+ 516500,2801 a
2
+ 3629745,964 a
3
- -110213,1403 = -559131,6777 a
2
+ -3436458,097 a
3
……………5 PLAGIAT MERUPAKAN TINDAKAN TIDAK TERPUJI
Persamaan 4 5
88339,42557 = 1743642,977 a
2
+ 559131,6777 a
3
X 559131,6777 -110213,1403 = -559131,6777 a
2
+ -3436458,097 a
3
X 1743642,977
→
4,939337123
10
= 9,74926023
11
a
2
+ 3,12628233
11
a
3
- 1,921723681
11
= -9,74926023
11
a
2
+ -5,991956027
12
a
3
+ -
1,427789969
11
= - 5,679327794
12
a
3
a
3
=
12 11
679327794 ,
5 427789969
, 1
− −
= 0,0251401225
Dari persamaan 4:
88339,42557 = 1743642,977 a
2
+ 559131,6777 a
3
88339,42557 = 1743642,977 a
2
+ 559131,6777 0,0251401225 88339,42557 = 1743642,977 a
2
+ 14056,63887 88339,42557 – 14056,63887 = 1743642,997 a
2
74282,7867 = 1743642,977 a
2
a
2
= 0,0426020622
Dari persamaan 1:
87,95806 = 1599,87097 a
1
+ -96,96774 a
2
+ 439,64516 a
3
87,95806 = 1599,87097 a
1
+ -96,967740,0426020622 + 439,64516 0,0251401225 87,95806 = 1599,87097 a
1
+ -4,131025691 + 11,05273318 87,95806 = 1599,87097 a
1
+ 6,921707489 87,95806 – 6,921707489 = 1599,87097 a
1
81,03635251 = 1599,87097 a
1
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